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980x^2-20x-800=0
a = 980; b = -20; c = -800;
Δ = b2-4ac
Δ = -202-4·980·(-800)
Δ = 3136400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3136400}=\sqrt{400*7841}=\sqrt{400}*\sqrt{7841}=20\sqrt{7841}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20\sqrt{7841}}{2*980}=\frac{20-20\sqrt{7841}}{1960} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20\sqrt{7841}}{2*980}=\frac{20+20\sqrt{7841}}{1960} $
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